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Home › Exams & licences › FCC Radiotelegraph Element 6 2014

6A20 - C = capacity in farads. Q = the measure of the quantity of charge of electricity in Coulombs. E = the applied voltage. So Q = CE:

  • Correct answer

    A.Determines the quantity of charge in a capacitor

  • B.Determines the Q of a circuit

  • C.Both A & B

  • D.None of the above

This question is one of 100 in FCC Radiotelegraph Element 6 2014. Test yourself on all of them.

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