6A20 - C = capacity in farads. Q = the measure of the quantity of charge of electricity in Coulombs. E = the applied voltage. So Q = CE:
- Correct answer
A.Determines the quantity of charge in a capacitor
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B.Determines the Q of a circuit
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C.Both A & B
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D.None of the above
This question is one of 100 in FCC Radiotelegraph Element 6 2014. Test yourself on all of them.
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